3x^2+12=2x^2+49

Solution for 3x^2+12=2x^2+49 equation:

3x^2+12=2x^2+49

We move all terms to the left:

3x^2+12-(2x^2+49)=0

We get rid of parentheses

3x^2-2x^2-49+12=0

We add all the numbers together, and all the variables

x^2-37=0

a = 1; b = 0; c = -37;
Δ = b2-4ac
Δ = 02-4·1·(-37)
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{37}}{2*1}=\frac{0-2\sqrt{37}}{2}
=-\frac{2\sqrt{37}}{2}
=-\sqrt{37}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{37}}{2*1}=\frac{0+2\sqrt{37}}{2}
=\frac{2\sqrt{37}}{2}
=\sqrt{37}
$